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Mathematics 15 Online
OpenStudy (anonymous):

what is the formula of f' and f''? the graph is posted below.

OpenStudy (anonymous):

OpenStudy (amistre64):

just follow the rules of differentation and derive them :) what part is giving you troubles?

myininaya (myininaya):

so f is given right? Where do you see that the graph has horizontal tangents?

myininaya (myininaya):

remember when you graph f' you are graphing the slope for each point i always start by seeing where my horizontal tangents are (where the slope is 0)

OpenStudy (amistre64):

i think its gonna be a bit more convoluted than that if you try to do it graphwise

myininaya (myininaya):

if the slope is 0, then f'=0 there if the slope is positive, then f'>0 there if the slope is negative, then f'<0 there

OpenStudy (amistre64):

[t e^t]' = t e^t + e^t [-e^(t^2)]' = -2t e^(t^2) ; this one id have to wonder about [+3]' = 0

myininaya (myininaya):

oh oops they give the equation lol

myininaya (myininaya):

or i mean the function

OpenStudy (amistre64):

lol ... its readable as long as you aint on an iphone :)

myininaya (myininaya):

gj amistre

OpenStudy (amistre64):

if i see it right: \[f'(t) = t \ e^t + e^t -2t\ e^{t^2} \]

OpenStudy (anonymous):

e^t (t+1) - 2e^t^2 t

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