Question

solve for u

6+(6/u-1)=(5/u+3)

Answer 1

6+6/u-1=5/u+3

multiply both sides by u

6u+6-u=5+3u

5u-6=5+3u

2u=11

u=11/2

Answer 2

or 5.5 if you want a decimal

Answer 3

wait the donominater are polynomials so it 6 /(u-1) and 5/(u+3)

Answer 4

6+6/u-1=5/u+3

multiply both sides by u

6u+6-u=5+3u

5u-6=5+3u

2u=11

u=11/2

Answer 5

dont forget medals

Answer 6

ok, thats more annoying

6+6/(u-1)=5/(u+3)

multiply by both denominators

6*(u+3)*(u-1)+6*(u+3)=5*(u-1)

Answer 7

expanding and multiplying,

6*(u^2+2u-3)+6u+18=5u-5

6u^2+12u-18+6u+18=5u-5

6u^2+18u=5u-5

Answer 8

get it all to one side

6u^2+18u=5u-5

6u^2+13u+5=0

Answer 9

then use the quadratic equation to get your roots

Answer 10

i forgot that how does it go

Answer 11

\[(-b \pm \sqrt{b^2-4AC})/2A\]

where the equation is of the form

Ax^2+Bx+C=0

Answer 12

\[6+\frac{6}{u-1}=\frac{5}{u+3}\text{ ; /6}\]
\[1+\frac{1}{u-1}=\frac{5}{6(u+3)}\text{ ; /5}\]
\[\frac{1}{5}+\frac{1}{5(u-1)}=\frac{1}{6(u+3)}\text{ ; common denom it}\]
\[\frac{u}{5(u-1)}=\frac{1}{6(u+3)}\text{ ; just a thought lol}\]

Answer 13

amis, those dont make the equation any easier

Answer 14

i dunno; looks pretty easy to me :)

\[\frac{u}{5(u-1)}=\frac{1}{6(u+3)}\text{ ; /u}\]
\[\frac{1}{5u(u-1)}=\frac{1}{6u(u+3)}\text{ ; /u}\]
\[\frac{1}{5u^2-5u}=\frac{1}{6u^2+18u}\text{ }\]
6u^2 +18u = 5u^2 -5u
u^2 +23u = 0
u(u+23) = 0

u = 0 or -23 ; did i miss it?

Answer 15

i missed it; 5u is bad bad bad

Answer 16

6u^2 +18u = 5u -5

6u^2 +13u + 5

Answer 17

you should get it down to my equation and have to use the quadratic equation anyway, your way just takes longer

Answer 18

have fun with it; i gots ta run ;)