Question

(3x^-2 y^3)/ (9x^3 y^-5)

=1)(3x^-5)/y^8
2)(xy^2)/3
3) 3xy^2
4)(y^6)/ 3x^5

Answer 1

x^n/ x^m = x^n-m

Answer 2

??

Answer 3

That's the rule to use. Just simplify.

Answer 4

12x^1 that wat i got

Answer 5

u just confuzed me more

Answer 6

I'm getting y^8/(3x^5)
3/9 reduced to 1/3
x^-2/x^3 reduces to x^-5 or 1/x^5
y^3/y^-5 reduces to y^8

Answer 7

You should get y^8/3x

Answer 8

sorry 3x^5 in the denom

Answer 9

the answer clostest to that has 3x^5 not 3x

Answer 10

are you sure the question is correct... i don't agree with any of the answers
\[\frac{3x^{-2}y^{3}}{9x^{3}y^{-5}} = \frac{y^{3+5}}{3x^{3+2}} = \frac{y^{8}}{3x^{5}}\]

Answer 11

Okay.
3*x^-2*y^3 3 x^-2 y^3
____________=__ * _____ * ______
9*x^3*y^-5 9 x^3 y^-5

Reduce each of those 3 fractions using the rule I gave to get

1/3 * x^-5 * y^8

Answer 12

Gotta go. Hope that explains it.