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b^2 + 49 How do I tell if both terms are squares?
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b^2 is pretty clearly the square of b yes?
yes...
how about 49?
see iff the other part of the equation is the product of the same number, here it is 7
and how did you find 7 as your answer. I see that it's correct, but how do I find it?
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keep practsing with the squared numbers uptil 256 and you would kinda memorize it.
7---7^2 = 49
Sry, still not quite getting a beginner's method here...
if a the number can be divisible by 1 number and it have the same as the answer
\[i^2=1\] \[2^2=4\] \[3^2=9\] \[4^2=16\] \[5^2=25\] \[6^2=36\] \[7^2=49\] \[8^2=64\] \[9^2=81\] question just asks you to recognize 49 as the square of 7
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