The edges of a rectangular solid have lengths 2x, 3x, and 5x. What is the total surface area of the solid?

Question

anonymous · Answer

I am confused by whether to use the formula or not, and also the question didn't specify the lengths are for width or height? How can I solve this?

anonymous · Answer

2*2x*3x+2*3x*5x+2*5x*2x

anonymous · Answer

your surface area will just be in terms of x

anonymous · Answer

well, x^2

anonymous · Answer

so 12x^2+30x^2+20x^2

62x^2 is your total surface area

anonymous · Answer

ryan, you dont square the lengths, there are no faces with the same length on both dimensions

anonymous · Answer

we are finding surface area.   yea, the lengths are squared.

anonymous · Answer

$$S=2(lh)+2(lw)+2(hw)$$
$$S=2(2x)(3x)+2(2x)(5x)+2(3x)(5x)$$
$$S=12x^2+20x^2+30x^2$$
$$s=62x^2$$

anonymous · Answer

the lengths are not squared, the general form of surface area of a rectangular solid is 

2*L*W+2*L*D+2*W*D

since L, W and D are all different, THERE ARE NO SQUARED TERMS

anonymous · Answer

thank you abstracted

anonymous · Answer

Thanks Abstracted and Jmay! I get it now :D

anonymous · Answer

Also thanks Ryan for your enthusiasm in answering my question! :)