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Mathematics 16 Online
OpenStudy (anonymous):

http://mywaycool.unl.edu/ishs_course_images/MTHH032060/evals/images/eval02g029.gif

OpenStudy (anonymous):

for x = –1, y = 5, and z = 3.

OpenStudy (dumbcow):

straight substitution

OpenStudy (aroub):

just substitute -1 by x and 5 by y and 3 by z !! :)

OpenStudy (anonymous):

im lost

OpenStudy (dumbcow):

actually simplify it first then substitute. -5/15 = -1/3 x^3/x^-7 = x^(3+7) = x^10 y^5/y^5 = 1

OpenStudy (anonymous):

needs to = -9,-3,-1 or 0

OpenStudy (anonymous):

so im confuzed

OpenStudy (dumbcow):

have you ever divided variables with exponents ? Ex: whats x^4/x^2

OpenStudy (anonymous):

100

OpenStudy (anonymous):

if x is 10

OpenStudy (dumbcow):

correct...x^4/x^2 = x^(4-2) = x^2 10^2 = 100

OpenStudy (dumbcow):

so thats all you're doing here, combining variables by subtracting their exponents

OpenStudy (anonymous):

but i dont understand the answer

OpenStudy (dumbcow):

well after you combine variables, you have to plug in the given values for the variables just like you used 10 for x above.

OpenStudy (anonymous):

is it -1

OpenStudy (dumbcow):

\[\rightarrow \frac{-x^{10}}{3z^{-2}} = \frac{-x^{10}z^{2}}{3} = \frac{-(-1)^{10}(3)^{2}}{3} = \frac{(-1)(9)}{3} = -3\]

OpenStudy (anonymous):

ty

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