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Mathematics
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OpenStudy (anonymous):
http://mywaycool.unl.edu/ishs_course_images/MTHH032060/evals/images/eval02g029.gif
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OpenStudy (anonymous):
for x = –1, y = 5, and z = 3.
OpenStudy (dumbcow):
straight substitution
OpenStudy (aroub):
just substitute -1 by x and 5 by y and 3 by z !! :)
OpenStudy (anonymous):
im lost
OpenStudy (dumbcow):
actually simplify it first then substitute.
-5/15 = -1/3
x^3/x^-7 = x^(3+7) = x^10
y^5/y^5 = 1
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OpenStudy (anonymous):
needs to = -9,-3,-1 or 0
OpenStudy (anonymous):
so im confuzed
OpenStudy (dumbcow):
have you ever divided variables with exponents ?
Ex:
whats x^4/x^2
OpenStudy (anonymous):
100
OpenStudy (anonymous):
if x is 10
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OpenStudy (dumbcow):
correct...x^4/x^2 = x^(4-2) = x^2
10^2 = 100
OpenStudy (dumbcow):
so thats all you're doing here, combining variables by subtracting their exponents
OpenStudy (anonymous):
but i dont understand the answer
OpenStudy (dumbcow):
well after you combine variables, you have to plug in the given values for the variables just like you used 10 for x above.
OpenStudy (anonymous):
is it -1
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OpenStudy (dumbcow):
\[\rightarrow \frac{-x^{10}}{3z^{-2}} = \frac{-x^{10}z^{2}}{3} = \frac{-(-1)^{10}(3)^{2}}{3} = \frac{(-1)(9)}{3} = -3\]
OpenStudy (anonymous):
ty
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