An engineering student watches an ant walk continuously along a wire for 1 minute. The shape of the wire can be given by the function f(t)=2t^2. Find the length (in meters) that the ant walked along the wire.
Are we assuming t is in seconds and not minutes?
The first thing you gotta do is to to find a function that describas de lenght of the curve you can do that either by a line integral or a find the legth path by some integration formual
Using \[L=\int\limits_{a}^{b}\sqrt{1+[f \prime(x)]^2}dx\] I get to \[L=\int\limits_{0}^{60}\sqrt{1+6t^2}dt\] And get stuck because I can't think of any trig substitution to complete the integral. So unfortunately I don't know...
6 is supposed to be 16 fyi
the integral cant be solve using a trig substitution which becomes \[\int\limits_{}^{}\sec ^{3}xdx\] then by integration by parts you can solve it \[\int\limits_{}^{}secx*\sec ^{2}dx\] U dv
thats the way to solve it
althoug I will recommend to solve this integral with the reduction formula Here is a great tool to solve any type of integral http://www.wolframalpha.com/input/?i=integrate+&a=*C.integrate-_*Calculator.dflt-&f2=sqrt%281%2B4t^2%29&x=9&y=3&f=Integral.integrand_sqrt%281%2B6t^2%29&a=*FVarOpt.1-_**-.***Integral.rangestart-.*Integral.rangeend--.**Integral.variable---.*--
from what I see you are just telling us the time and the "shape" of the path taken , but we might need some information regarding the position (s(t))or velocity(v(t))
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