A man Standing on top of A cliff 50m high is in line with two buoys whose angles of depression are 18degree and 20degree. Calculate the distance between the buoys.
Use tan function: tan = opp/adj Let x be distance from cliff to 1st buoy \[\tan 20 = \frac{x}{50}\] Let y be distance from cliff to 2nd buoy \[\tan 18 = \frac{y}{50}\] Distance between buoys is y-x
Well, the first buoy is \[50\tan 18\]50tan(18) meters away (basic right angled triangle) The second one is 50tan(20) meters away. We calculate these and get a difference.
The answer is 16.5m
thats the idea..my angles may be off
depression meaning angle of line from top of cliff hmm that means the compliment is the angle you want to take tangent of
Ah right.
\[1st = 50*\tan 70 =137.37\] \[2nd = 50*\tan 72 = 153.88\] \[153.88-137.37 = 16.51\]
tan (90-20) tan(90-18)
those should be the angle you should use ..
Thank
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