Help : Determine if y=2x+1 is a function.
how do you determine it?
yea it is .....
Yes it is very much a function? What conditions are required for determining?
if every x has a different y then yes it is
angela; that is not quite right, might be lost in translation tho
Btw Thank you all for jumping in to help me I do not see this happen to every ones problem :P
if every x value produces a single y value
amistre? why? if a a x produces two y values then???
Crap is it ok to give a good answer to every one who helped? :S they are all good :P
hmmmm...tht's wht i meant Amistre :)
the actual function is \[\{(x,y)|y = 2x+1\}\]
a function is defined as a special relation in which the dependant variable can be mapped onto only one range element. So that when we are trying to determine the results of a given model we can predict an outcome
It is a copy of the problem i can send pic if you like?
if you want a function you really have to write it as one. so we say \[y=2x+1\] DETERMINES a function, not IS a function
y^2 = x+2; can be graphed, and if we use a conventional system of a vertical y axis and a horizontal x axis; each x value produces 2 results
determines a function is good :)
A function is a subset of a Cartesian (e.g. \(\mathbb{R}\times\mathbb{R}\) )product such that, if (x,a) and (x,b) are in the subset then a=b
so a relation in which one x produces two y's is not a function? then what is it called? for eg x^2=y?
x^2 =y can be considered a function; if we use conventional graphing means
y^2=x i mean
what do you mean by conventional ?
x=y^r is only a funtion if r=1
I think i got lost lol
the standard graphing system denotes y as a vertical axis and x as a horizontal axis
if those conventions are not kept than all bets are off :)
got it : )
that helped :D
but we can plot y^2=x on a graph using conventions too no?
plotting is a result of being a "relation". A function is a "special type of relation"
So are these relations classified further? and what are the classes then?
and a one to one relation is a special type of "function" lol
one is to many is a function? but many is to one is not ight?
wow thank you so much for helping me under stand it :D i love how there are like 15 people looking at my problem :D
the whole gambit of classes or relations, i dont think I know of; just the basic few
It should be noted that a graph is a function. In fact you are just setting up a injective map between the function (set of ordered pairs) and \(\mathbb{R}^2\) the vector space.
one to one is a function that has an inverse many to one can be a function one to many is a relation
ok i have a question how is function determined in 3d space
ya exactly! How can we talk of function in 3 dimensions>?
easy; when i swing a hammer in 3d space; the function is to drive a nail :)
right! but what are the conditions that will apply? like for 2 dimensions?
but how do you say that it is function
we can also take angular displacement or angular velocity as a function in 3 dimension.
as long as what your mapping and what your mapping onto conforms to the standards; its good
\[f:\mathbb{R}\to\mathbb{R}^3\]\[f:\mathbb{R^3}\to\mathbb{R}\]\[f:\mathbb{R^3}\to\mathbb{R^3}\] Do you see now talking about functions in 3-space is ambiguous.
In fact you are just setting up a injective map between the function (set of ordered pairs) and R2 the vector space. I couldnt get this alchemista.
What does that mean? r^2?? r means Real numbers?
When you raise a field to a power you are taking the Cartesian product of the field
\[\mathbb{R}^2 = \mathbb{R}\times \mathbb{R}\]
R^3 means you are taking the cartesian product twice?
\[\mathbb{R}^3 = \mathbb{R} \times \mathbb{R} \times \mathbb{R}\]
that would be an (x, y, z), where x, y, and z are real numbers.
f:R→R3 f:R3→R f:R3→R3 Do you see now talking about functions in 3-space is ambiguous. why is it ambigious then?
I said it was ambiguous because when you talk about functions in 3space it could mean more than one thing.
From which space to which space?
This is good stuff right here xD
Can you give an example alchemista?
I just showed you above, those three examples you pasted again.
no no an example can you explain by taking a function?
Oh err someone else think of a real world example
What do you want an example of? a function from R^3 to R^3? or R^3 to R? or whatever combination? lol
sphere is it a function in 3d space
A combination which shows that three dimensional function can be ambiguous?
a sphere is a set of points in R^3 that satisfy some condition.
No, I said that when you said a 3d function, it doesn't tell us what you mean. Not that a function is ambiguous.
yes a sphere can be a good example
i think i should read and then talk with you guys sorry for the trouble
I think what alchemista is saying is that if you just say "a 3d function", its ambiguous because we dont know what the inputs and outputs are.
See final query here Like a relation in a 2 dimensional convention be not a function can similarly a case in 3 dimensional relation occure? Yes or no plz give 1 eg if possible.. yes ishaan i feel the Same now
You have to be more specific, like, "a function from R to R^3" that tells us it takes in one dimensional objects and spits out 3 dimensional objects
Yes joemath that's what I mean
http://en.wikipedia.org/wiki/Three-dimensional_graph look at his so unusual ..i never saw something like that
ok say a function from r^3 to R^3
Give me one eg of such a function
T(x,y,z) = (x+y, y+z, x+z)
in theory you have to do that anyway. to specify a function you are supposed to define the domain and range no matter what dimension you are in
thats true satellite.
why is it r^3 to r^3 but? I am not getting that!
which is why math teachers should stop with problems that say "find the domain of..."
Lets just start with linear transformations
Something from R^3->R^3 could take some point in 3space and rotate it for instance.
its R^3 to R^3 because your input is 3 tuple (did i say that right?)
You can't really graph that.
yeah =/
sorry i didn't knew that
yes alchemista.. i took a point in 3-d n rotated it then??
Oh i think i am taking it in a wrong way.. Sorry for the trouble i will do some more research and ask thanks for your time too
<.< ask some more lol
wow you all or just grate
is sin(x+y+z) a function?
hmm... if you say "its a function from R^3 to R" then yes :P
because you need 3 inputs for it to great one output.
its a f(x,y,z) = k or whatever 4th variable you want to use lol
to create* i dont know why i said great lol
Oh yes! now i get it! 3 inputs to 1 output makes it a R^3-R function right?
right.
well yes yes i got it!!
an example of a function from R^3 to R we use all the time is volume. V(l,w,h) = l*w*h three inputs, a one dimensional output.
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