Question

Let logA=3 logC=2 logD=5.
What is the value of logA^3D^4/C^2?

A. 176
B. 4,218.75
C. 25
D. 33

Answer 1

i got 1875 but thats not an option :/

Answer 2

hmmm i will look into it if no one can help

Answer 3

Okay
\[3logA + 4logD - 2logC\]

Answer 4

is it log a ^4 times log d^3 or just log a ^4 d^3? Those are two different things

Answer 5

25

Answer 6

C

Answer 7

http://www.wolframalpha.com Might help you

Answer 8

3logA+4logD−2logC IN THIS EQUATION WHEN we replace value logA=3 logC=2 logD=5, we can obtain = 25

Answer 9

are you OK dear kassia?

Answer 10

yeah i got it