Question

Prove the trigonometric identity:
(csc^2x)/(cotx)=cscxsecx

Answer 1

csc²(x) / cot(x)
= csc(x) * csc(x)/cot(x)
= csc(x) * [1/sin(x)]/[cos(x)/sin(x)]
= csx(x) * [1/sin(x)]*[sin(x)/cos(x)]
= csc(x) * [1/cos(x)]
= csc(x) sec(x)

Answer 2

you are pro at trig identities O.o

Answer 3

heheh thanxx (A)

Answer 4

Pretty much, you're is kinda saving my life currently. I greatly appreciate it. (:

Answer 5

:D glad i cd help

Answer 6

Quick question, how does the /(cosx/sinx) get to *(sinx/cosx) ??

Answer 7

sory i was away
when dividin 1/sinx by cosx/sinx
its tha same as 1/sinx * sinx/cosx

\[(1/a)\div b = (1/a)\times1/b\]