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OpenStudy (aravindg):
(m+1)x^2+2mx+3=0 sum of roots 1 m=?
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myininaya (myininaya):
\[b=\frac{-2m \pm \sqrt{(2m)^2-4(m+1)(3)}}{2(m+1)}=\frac{-2m \pm \sqrt{4m^2-12m-12}}{2(m+1)}\]
\[=-\frac{-2m \pm \sqrt{4(m^2-3m-3)}}{2(m+1)}=\frac{-2m \pm 2\sqrt{m^2-3m-3}}{2(m+1)}\]
\[=\frac{-m \pm \sqrt{m^2-3m-3}}{m+1}\]
\[\frac{-m +\sqrt{m^2-3m-3}}{m+1}+\frac{-m - \sqrt{m^2-3m-3}}{m+1}=1\]
myininaya (myininaya):
\[\frac{-2m}{m+1}=1\]
myininaya (myininaya):
\[-2m=m+1, m \neq -1\]
myininaya (myininaya):
\[-2m-m=1 => -3m=1 => m=\frac{-1}{3}\]
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OpenStudy (anonymous):
Oh dear, no
alpha + beta = -b/a (standard formula)
OpenStudy (aravindg):
so wat is answer?
OpenStudy (anonymous):
Am I misunderstanding the question?
myininaya (myininaya):
sum of roots is 1 right?
OpenStudy (aravindg):
yes
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myininaya (myininaya):
ok oh and also estudier
-2m/(m+1) is -b/a
myininaya (myininaya):
and this is suppose to be one according to what he has
OpenStudy (aravindg):
answer is -1/3?
myininaya (myininaya):
if i made no mistake
myininaya (myininaya):
but i'm known for making alot of mistakes
maybe you can trust me and maybe you can't
who knows
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myininaya (myininaya):
but it looks good to me
OpenStudy (aravindg):
i truust u
myininaya (myininaya):
lol
OpenStudy (anonymous):
U can go do my question now:-)
OpenStudy (aravindg):
lol
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myininaya (myininaya):
ok i'm gonna get on my laptop and move to the other room
i'm about to watch white collar
OpenStudy (aravindg):
u hav a fan
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