Derive the formula for the axis of symmetry to a quadratic equation.

Question

anonymous · Answer

you just helped someone find the vertex of a parabola using the formula and now you want somemone to derive it for you?

anonymous · Answer

Anytime I write a question it usually "for fun".. :)

anonymous · Answer

U surely don't HAVE to..  :)

anonymous · Answer

okay thanks for the info

anonymous · Answer

Find the derivative and equate it to zero solve for x to get ur ans

anonymous · Answer

$$y=ax^2+bx+c$$
$$y=a(x+\frac{b}{a})+c$$
$$y=a(x+\frac{b}{2a})^2+\color{red}{\text{who cares}}$$ since first term is a perfect square it will be greater than or equal to zero if a is positive, less that or equal to zero if a is negative and it will be zero (so that is the max or min) if 
$$x=-\frac{b}{2a}$$

anonymous · Answer

derivative my foot

anonymous · Answer

If you don't care BOUNCE

anonymous · Answer

i don't care because if i need to find it i can alway replace x by 
$$-\frac{b}{2a}$$ i just don't care to try to keep track of what i added and subtracted. waste of time since i can find it easily

anonymous · Answer

I see.