let f(x)=(absolute val of x)/(x). show that f(x)=1,x>0 f(x)=-1,x<0 find the domain and range of f(x)
domain all numbers except 0
range is 1 and -1
i kind of have to explain how i know that though
\[f(x) = \frac{|x|}{x} = \left\{\begin{array}{rcc} 1 & \text{if} & x >0 \\ -1& \text{if} & x < 0 \end{array} \right.\]
Well, if x > 0 then |x| = x Therefore |x|/x = x/x = 1 If x < 0 then |x| = -x Therefore |x|/x = -x/x = -1
ok well we start with \[ |x| = \left\{\begin{array}{rcc} x & \text{if} & x \geq 0 \\ - x& \text{if} & x < 0 \end{array} \right.\]
that is the definition. then divide by x to get what i wrote above exactly.
what polpak said. hello polpak
Nice latex btw =)
merci. i stole it from zarkon
And I shall steal it from you ;p Wouldn't have thought to lay that out using an array
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