An object is launched vertically at 25.9 meters per second from a 10 foot tall platform. Using the projectile motion method, determine how long it will take for an object to reach maximum height. What is the maximum height?

Question

anonymous · Answer

-16t^2 + vt + s

anonymous · Answer

-16t^2 + 25.9t + s
Now, solve for the vertex, and then t

anonymous · Answer

oops 24.5 meters

amistre64 · Answer

gotta convert meters to footers i think or visaversa

anonymous · Answer

-16t^2 + 24.5t + 10
Height: 19.36 feet
Time: .765 Seconds.

amistre64 · Answer

your units are mismatched; make them speak the same language

amistre64 · Answer

-4.9t^2 +24.5t + (10 feet in meters)

                      OR

-16t^2 + (24.5 in footers) t + 10

anonymous · Answer

you are right amistre64, I should have put meters

anonymous · Answer

maximum height is 34.19 m taking 10 foot as refference

anonymous · Answer

I just don't think in meters and wrote 10 feet. arggghh. *smacks forehead*

anonymous · Answer

time taken is 1.09 second

anonymous · Answer

thanks so much

amistre64 · Answer

if ALL your measures are in meters ... then

-4.9t^2 +24.5t +10  is th  equation :)

anonymous · Answer

just apply the formula for maxmium height 
H( max)=v^2 sinx^2/2g