Question

Can someone please help me with this problem?

Answer 1

For a) use t = 2, compute P
For b) use P = 7000, solve for t

Answer 2

5005 first one

Answer 3

dont think i understand. can you please just give me the answer so i can work it through and check

Answer 4

how did you get that shanli

Answer 5

in your calculator you have to type :
14/(1+4(e^-.8) and then the answer is 5.004 in which u should multiply it by 1000 gives you 5004.7 --> round it 5005

Answer 6

what about for second one

Answer 7

and how did we find the -.8 ? its t times -.4 in the question

Answer 8

do you know what "ln" is ?

Answer 9

natural log

Answer 10

yep. so: this time you have the p, u want the t:
7+28 e^(-0.4t) = 14
1+4 e^(-0.4t) = 2
4 e^(-0.4t) = 1
e^(-0.4t) = 1/4
Now You have to use LN to find what the Power of e has been !
So you have : e^something=1/4
ln 1/4= -0.4t
-ln(1/4)/0.4=t
t=3.5

Answer 11

so the anser is 3.5 years?

Answer 12

actually it's 3.46