f(x)=11x+7 f-1(x)=__________ can anyone help me here with finding the inverse step by step?
make it x = 11y + 7 and solve for x
solve for y sorry
so you should get (x-7)/11
so (x-7)/11 is my answer?
yes
thank you a bunch, hey can you help me solve a few others? but can you show me step by step how you are getting the answer?
yea go ahead
i'll redo the first one...instead of f(x) just make it x....then replace the x's in the equations with y...so you get x = 11y+7 step 1. move the 7 to the other side....x-7 = 11y. step 2. isolate your variable by dividing by 11. so you get y = x-7/11
f(x)=3-4x find f-1(4)
x = 3-4y......x-3 = -4y ........x-3/ -4 is the inverse...but now they want to know what f -1 (4) is so you plug 4 for x into the inverse equation so it 4-3/-4 which is -1/4 as your answer
awesome
this is trickier, If f(x)=x+7 and g(x)=x-7 (a) f(g(x))= (b) g(f(x)= (c) Thus g(x) is called an_________function of f(x)?
A) rewrite this as f(x) times g(x) b/c that's really what it's asking. so it's (x+7)(x-7) and now you just foil it out. so it's x^2 -7x+7x-49 and the 7x's go away b/c -7x +7x is 0....so your answer for A is x^2-49
for B. it's just the opposite. it's g(x) times f(x) therefore it's now (x-7)(x+7) which will come out to the same exact answer. and when you see a binomial like x^2 - 49 it's known as the difference of squares since 7^2 is 49. so when you see something like x^2 -25....u can just see it's (x-5)(x+5). So your answer for C is difference of squares but i guess their looking for inverse as the missing word? I honestly don't know about C.
do i include parentheses for a and b?
yes
u mean like do you include parentheseis around x^2-49? that doesn't matter b/c it's just one term
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