Question

Helps:

Prob :1
Use elimination to solve the system of equations given by -7x + 3y = 14 and 7x - 2y = -14

A: (-2, 0)
B: (1, -2)
C: (0, -2)
D: (0, 2)

Prob 2:
Use elimination to solve the system of equations given by 10x - 40y = 60 and 15x + 40y = -10.

A: (0, 1)
B: (1, 1)
C: (-2, -2)
D: (2, -1)

Notes: If you could teach me how to do it when you help me it would be grate, But trying to keep it fast

Answer 1

there are 3 more just like it so i will try to get them right after someone help me.. so more Medals for every one xD

Answer 2

Helps ^

Answer 3

A and D

Answer 4

Thanks but i need to learn it

Answer 5

Math can to brake it down in to Small steps like supper small xD

Answer 6

prob 2
10x - 40y = 60 and 15x + 40y = -10.
add both equations
you will get 25x=50
so x=50/25=2
now substitute x value in one of the equation
10(2)-40y=60
-40y=60-20
y=40/-40
y=-1

Answer 7

so for Use elimination to solve the system of equations given by 3x - 2y = 12 and 3x + 5y = 33.

I add 3x - 2y = 12 + 3x + 5y = 33

Answer 8

prob 1
-7x + 3y = 14 and 7x - 2y = -14
add both equations
you will get y=0
now substitute y value in one of the equation
7x-2(0)=-14
x=-14/7
x=-2

Answer 9

Can you show how to add both equations

Answer 10

-7x+3y=14
7x-2y=-14
-------------
0+y=0

Answer 11

3x - 2y = 12 and 3x + 5y = 33.
in this case you should subtract 2nd equation from 1st equation

Answer 12

err we need a whiteboard

Answer 13

do you happen to know of one we can use?

Answer 14

http://www.twiddla.com/580173

Answer 15

can you show me on there