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What is the maximum number of possible solutions for the system shown below? x^2-4y^2=64 x^2+y^2=36 A. 2 B. 3 C. 1 D. 4
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Ellipse + hyperbola max 4
well \[y = \pm \sqrt{28/3}\] \[x = \pm \sqrt{304/3}\] how many is that?
four
yep :)
but they have to be pairs to be called solution so 2
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(x,y) (-x,y) (x,-y) (-x,-y) All solutions because the variable is being squared in the equations
i don't remenber it now but last year when we coped with these systems only quite a few had 4 solutions....
or look at estudiar answer if you draw an ellipse and a hyperbola, that can cross at 4 points
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