What is the maximum number of possible solutions for the system shown below?

x^2-4y^2=64
x^2+y^2=36

A. 2
B. 3
C. 1
D. 4

Question

What is the maximum number of possible solutions for the system shown below?

x^2-4y^2=64
x^2+y^2=36

A. 	2
  		B. 	3
  		C. 	1
  		D. 	4

anonymous · Answer

Ellipse + hyperbola max 4

dumbcow · Answer

well
$$y = \pm \sqrt{28/3}$$
$$x = \pm \sqrt{304/3}$$
how many is that?

anonymous · Answer

four

dumbcow · Answer

yep :)

anonymous · Answer

but they have to be pairs to be called solution so 2

dumbcow · Answer

(x,y)
(-x,y)
(x,-y)
(-x,-y)

All solutions because the variable is being squared in the equations

anonymous · Answer

i don't remenber it now but last year when we coped with these systems only quite a few had 4 solutions....

dumbcow · Answer

or look at estudiar answer
if you draw an ellipse and a hyperbola, that can cross at 4 points