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multiply and simplify: (x^2+2x+2)(x^2-2x+2)
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method or answer?
answer is \[x^4+4\]
method
what is more interesting that multiplying this out doing 9 multiplications is to turn \[x^4+4\] into \[(x^2+2x+2)(x^2-2x+2)\]
you do it as follows. add and subtract \[4x^2\] and write \[x^4+4x^2+4-4x^2\] which is the difference of two squares
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now you have \[(x^2+2)^2-4x^2\] and the difference of two squares factors so you get \[(x^2+2-2x)(x^2+2+2x)\] which is what you started with
this is sometimes called "completing the square" or the "sophie germain" trick
otherwise you just have to multiply out and it is a pain. \[(x^2+2x+2)(x^2-2x+2)\] \[x^4-2x^3+2x^2+2x^3-4x^2+4x+2x^2-4x+4\] and collect terms to get your answer
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