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Mathematics 8 Online
OpenStudy (anonymous):

multiply and simplify: (x^2+2x+2)(x^2-2x+2)

OpenStudy (anonymous):

method or answer?

OpenStudy (anonymous):

answer is \[x^4+4\]

OpenStudy (anonymous):

method

OpenStudy (anonymous):

what is more interesting that multiplying this out doing 9 multiplications is to turn \[x^4+4\] into \[(x^2+2x+2)(x^2-2x+2)\]

OpenStudy (anonymous):

you do it as follows. add and subtract \[4x^2\] and write \[x^4+4x^2+4-4x^2\] which is the difference of two squares

OpenStudy (anonymous):

now you have \[(x^2+2)^2-4x^2\] and the difference of two squares factors so you get \[(x^2+2-2x)(x^2+2+2x)\] which is what you started with

OpenStudy (anonymous):

this is sometimes called "completing the square" or the "sophie germain" trick

OpenStudy (anonymous):

otherwise you just have to multiply out and it is a pain. \[(x^2+2x+2)(x^2-2x+2)\] \[x^4-2x^3+2x^2+2x^3-4x^2+4x+2x^2-4x+4\] and collect terms to get your answer

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