Question

help ,Please!
A certain game has two stacks of 30 tiles with pictures on them. In
the first stack of tiles, there are 10 dogs, 4 cats, 5 balls, and 11 horses. In the
second stack of tiles, there are 3 flowers, 8 fish, 12 balls, 2 cats, and 5 horses. The top tile in each stack is chosen. Find each probability.

Answer 1

probability of what?

Answer 2

1) P (each a ball):

Answer 3

2) P (exactly one is a ball):

Answer 4

2) P (exactly one is a ball):
5/30=1/6 ?

Answer 5

#2 is not correct

Answer 6

exactly one is a ball.
first one is
+ second one is
- they both are

Answer 7

\[\frac{1}{6}+\frac{2}{5}-\frac{1}{6}\times \frac{2}{5}\]

Answer 8

P (exactly one is a ball)=P(1st is ball and 2nd is not a ball)+P(1st is not a ball and 2nd is a ball)

Answer 9

i hope we get the same answer either way

Answer 10

we don't

Answer 11

damn then i am wrong and now i have to think

Answer 12

I get \[\frac{13}{30}\]

Answer 13

ok so what is the flaw in my thinking that
\[P(A\cup B)=P(A)+P(B)-P(A\cap B)\] i am sure you are right, just asking

Answer 14

with that formula both could be balls

Answer 15

oooooooooooh yes. of course. thanks

Answer 16

i guess i could subtract off twice then yes?

Answer 17

yes

Answer 18

of course. exclusive or. got it thanks

Answer 19

yes

Answer 20

B=30-12=18
B=18/30

Answer 21

for #2)

doing it the way i typed above

\[\frac{5}{30}\frac{18}{30}+\frac{25}{30}\frac{12}{30}\]

Answer 22

you could also do this

P (exactly one is a ball)=1=P(both balls or both not balls)
\[=1-\frac{5}{30}\frac{12}{30}-\frac{25}{30}\frac{18}{30}\]

Answer 23

1-P(both balls or both not balls)

Answer 24

1) = 13/30 ?

Answer 25

for #2 yes ...#1 no

Answer 26

1)\[\frac{1}{15}\]

2)\[\frac{13}{30}\]