ALGEBRA 2 Using complete sentences, describe how you would analyze the zeros of the polynomial function f(x) = 7x^5 + 15x^4 – x^3 + 4x^2 – 6x – 11 using Descartes’ Rule of Signs. Be sure to provide the answer in your explanation.
why are you studying algebra 2?
what do you mean why? i did NOT fail it, i'm trying to get ahead so i'm taking it online but i don't understand this problem.
do you like math?
uh, sure? can you help me with this question?!
of course
so,
do you plan to be mathematician?
ok dude i'm tired of this. bye.
alrigh i will help
now, what do you know about the descartes rule of signs?
Yes. I answered like 10 other questions about it but this one I tried and I got a ridiculous answer! I got 3 or 1 real positive, 4 or 2 real negative, and i didnt get an answer for complex.
so, you do know something, thats good, at least your not just trying to cheat
lets begin
is my answer right though? and there is 0 possibility for complex.
so, how many sign changes do we have in f(x), i count 3
i count 3. and then subtract 2, so 3 or 1 possible positive.
now, when we substiute in -x what do we get, how many sign changes? i count 2 right?
so 3 positve real roots can exist, and 2 negative real roots
I counted 4? but thats the trouble i am having, what do you do in the sign changes? can you please step by step do sign changes? because i got (after the sign change) f(-x) = -7x^5 - 15x^4 + x^3 - 4x^2 + 6x - 11.
okay, so we have orginal f(x)=7x^5 + 15x^4 – x^3 + 4x^2 – 6x – 11 right? i count 3 sign changes
Yes...
now when i replace with -x, we have f(-x)=–7x5 + 15x4 + x3 + 4x2 + 6x – 11, right? here i count 2 changes
thus: 3 positve real roots can exist, and 2 negative real roots
why did you only replace 7x5 and x3 and 6x? are you supposed to skip one each time or do it as binomials or something?
why, b/c look at the exponets, if i put a negative number in x^2 it will come out positive. If i put a negative number in x^3 it will still be negative.
get it?
If i place a negative number in: even exponets=positive odd expoent=negative
Ok! I see now, alright thanks!
thats right you just got owned
jk
Join our real-time social learning platform and learn together with your friends!