Question

Zarkon is it just 14 or -14?

Answer 1

\[\sqrt{-196}=14i\]

is that what you are talking about

Answer 2

\[\sqrt{-196} = \sqrt{-1}\sqrt{196} = i\sqrt{196}\]

Answer 3

yess but y did u put i?

Answer 4

imaginary

Answer 5

http://en.wikipedia.org/wiki/Complex_number

Answer 6

Alchemista

Answer 7

i need ur help

Answer 8

if you don't just want the principle value then it is \[\pm\] the given answer.

Answer 9

there is no real solution to
\[\sqrt{-196}\]
as -192<0
and -14^=196
and14^2=196
so the imaginary number i=sqroot-1 is used instead

Answer 10

There is no real number whose square is a negative number. That's why the only solutions like on the complex field.

Answer 11

so theres no solution to 196 sqaure root?

Answer 12

Yes, a real solution to \(\sqrt{196}\) but not \(\sqrt{-196}\)

Answer 13

the square root of 196 is \[\pm14\]

Answer 14

yes i meant -196

Answer 15

There are no real numbers whose square is a negative number. So for any negative number you will not have a real square root.

Answer 16

remember thax x^2=x*x
and never x*-x
which would give a negative solution.

Answer 17

Read about complex numbers.

Answer 18

ok tanks