Question

Determine whether each situation involves a
permutation or a combination. Then find the number of possibilities
1). 8 cars in a row parked next to a curb
2). a hand of 6 cards from a standard deck of cards

Answer 1

permutation sees different orders as different elements

combinations see sets as an element so order doesnt matter

Answer 2

8 cars can be parked in different ways; 8! ways

6 cards from a standard deck are the same regardless of how you hold them: P(52,6),6!

Answer 3

2)
52!/(52-6)!*6! ?

Answer 4

yes

Answer 5

1). 8 cars in a row parked next to a curb
here arrangement is considered so it's permutation
8P1=8


2). a hand of 6 cards from a standard deck of cards
here it's a cobination as no arrangements is considered
52C6=

Answer 6

C(n,r) is just P(n,r)/r!

Answer 7

ty

Answer 8

\[\dbinom{52}{6}=\frac{52\times51\times 50\times 49\times 48\times 47}{6\times5 \times 4\times 3\times 2}\]

Answer 9

yw

Answer 10

this is of course a whole number, so cancel everything before you multiply

Answer 11

yes

Answer 12

\[\dbinom{52}{6}=\frac{52\times51\times 50\times 49\times 48\times 47}{6\times5 \times 4\times 3\times 2}=52\times 17\times 10\times 49\times 47\]