can you please help me solve quadatric equation 4x^2-12x+9=0
(3-2 x)^2 = 0 Factor x = 3/2
\[4x^2-12x+9=(2x-3)^2=0\]\[(2x-3)^2 = 0\]\[(2x-3) = 0\]\[2x = 3\]\[x =3/2\]
Never mind, I got it wrong. >___> Sorry. :'D
factoring is great, when it can be done; but completing the square is the long version of the quadratic formula
Why complete the square when you can factorise/use the formula?
4x^2-12x+9=0 4(x^2 -3x+___) = -9 + 4(___) 4(x^2 -3x+9/4) = -9(4)/4 + 4(9/4) 4(x-3/2)^2 = 0 (x -3/2)^2 = 0 x = 3/2 maybe?
completeing the square is just a good thing to know for other conics :)
Exactly, no point doing extra work for nothing.
and can be less of a headache when working the math
unles syou do it by calculator :)
Only if you are not sure about the formula, which completes the square for you
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