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OpenStudy (anonymous):
expand log(sqrt of x) and then log(a^2b)
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OpenStudy (anonymous):
1.) log (sqrt (x)) = log x^(1/2) = 1/2 log(x)
2.) log (a^(2b)) = 2b log (a)
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
what is 2?
OpenStudy (anonymous):
a^ ?
OpenStudy (anonymous):
what 2?
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OpenStudy (anonymous):
i cant read what was written for number 2 it doesnt make sense
OpenStudy (anonymous):
a^(2b)
isnt that what you were asking for in the question?
OpenStudy (anonymous):
ya is that written as a to the 2b?
OpenStudy (anonymous):
yes it is. were you asking for log(a^2*b)?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
that would be log (a^2) + log (b) = 2log(a) = log(b)
OpenStudy (anonymous):
that should be 2log(a) + log(b)*
OpenStudy (anonymous):
lol so i need to rewrite the whole thing im confused. how does it look showin work
OpenStudy (anonymous):
is it log(a^(2b))??
OpenStudy (anonymous):
is it log(a^(2b))??
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OpenStudy (anonymous):
is it log(a^(2b))??
OpenStudy (anonymous):
is it log(a^(2b))??
OpenStudy (anonymous):
it is log (a^2*b) = log (a^2) + log (b)
from the multiplication rule
= 2 log(a) + log(b)
from the exponent rule
OpenStudy (anonymous):
Or you can just use the multiplication rule entirely:
\[log(a^2b) \]\[= log(a\cdot a \cdot b) \]\[= log(a) + log(a) + log(b)\]\[=2log(a) + log(b)\]
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