Question

apply the quadratic formula to find the roots of the given function, and then graph the function. g(x) = 5x^2+13x-6
please show work for credit

Answer 1

so you want it all written out? use
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\] with
\[a=5,b=13,c=-6\] you get
\[x=\frac{-13\pm\sqrt{13^2-4\times 5\times -6}}{2\times 5}\]
\[x=\frac{-13\pm\sqrt{169+120}}{10}\]

Answer 2

yes please I am having a hard time understanding this

Answer 3

then we simplify right

Answer 4

what happened to my post? i wrote it all out

Answer 5

ii guess all that is left is
\[x=\frac{-13\pm\sqrt{289}}{10}\]

Answer 6

I don't know you disappered from the screen

Answer 7

something funny going on here. ok did you get
\[x=\frac{-13\pm\sqrt{289}}{10}\]?

Answer 8

yes

Answer 9

now
\[\sqrt{289}=17\] so your two answers are
\[\frac{-13-17}{10}=\frac{-30}{10}=-3\]

Answer 10

and
\[\frac{-13+17}{10}=\frac{4}{10}=\frac{2}{5}\]

Answer 11

hope these went through ok. two solutions, -3 and 2/5

Answer 12

so now what do I graph?