Question

tan^2x=(1-cos2x/1+cos2x)
A. True
B. False

Answer 1

true

Answer 2

[ (1-cos(2x)) / (1+cos(2x)) ]

[ (1-cos(2x)) / (1+cos(2x)) ] * [ (1-cos(2x)) / (1-cos(2x)) ]

[ (1 - 2cos(2x) + cos^2(2x)) / (1 - cos^2(2x)) ]

[ (1 - 2* (2 cos^2(x) - 1) + (2 cos^2(x) - 1)^2 / (1 - (2 cos^2(x) - 1)^2 ]

[ (1 - 4cos^2(x) + 2 + (4cos^4(x) - 4cos^2(x) + 1) / (1 - (4cos^4(x) - 4cos^2(x) + 1) ]

[ 4 - 4cos^2(x) + 4cos^4(x) - 4cos^2(x) / ( -4cos^4(x) + 4cos^2(x) ) ]

[ 4(cos^4(x) - 2cos^2(x) + 1) / 4( -cos^4(x) + cos^2(x) ) ]

[ cos^4(x) - 2cos^2(x) + 1 / ( -cos^4(x) + cos^2(x) ) ]

[ ( cos^2(x) - 1 )^2 / -cos^2(x)( cos^2(x) - 1 ) ]

[ ( cos^2(x) - 1 ) / -cos^2(x) ]

[ -sin^2(x / -cos^2(x) ]

tan^2(x)

Answer 3

so it is true

Answer 4

abhishek dere is no need of doing dat..1-cos^2x=sin^2x and 1+cos^2x=cos^2

Answer 5

thanks for short method:)