Question

What is the 32nd term of the arithmetic sequence where a1 = 14 and a13 = –58?

Answer 1

The answer is -172. Here is how you get the answer:

As you move through the sequence each one decreases by 6

Therefore, the formula is:

14-6(n-1) where n is the term you are looking for

14-6(32-1)
14-6(31)
14-186=-172

Answer 2

thanks for showing me how to do it

Answer 3

You're welcome