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what is the sum of the arithmetic sequence 3,9,15, if there are 36 terms
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You should have a formula for finding this sum. n is the number of terms, so for this problem n=36. d is the common difference. It can be found by subtracting the second term minus the first.
i no its 6
u didn't try the formula i posted in ur previous post?
i guess not
Then the formula to use is \[(n/2) * [2a_{1} + (n-1)*d]\]
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y?just use the formula n u will get the sum, it needs simple airthmetics using a calculator
yes stacey is right
\[a_{1} =3\] since 3 is the first term.
i got 151
sorry wrong post
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i believe the answer is 4234
That seems too big.
3468
3888
n/2 = 36/2 = 18 so we have 18*[2*3 + (36-1) * 6]
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are either of those answers right
3888 is correct.
3468 or 3888
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