Question

Someone please help!!
What are the coordinates of the foci of the conic section shown below?

(y+2)^2/25- (x-3)^2/4=1
A. (3±√21, -2)
B. (3, -2±√29)
C. (3, -2±√21)
D. (3±√29, -2)

Answer 1

C. (3, -2±√21)

Answer 2

thank you!!

Answer 3

:)

Answer 4

a=5 and b=2
c^2 = 25 + 4 = 29
So we add and subtract √29 to the y-coordinate.

Answer 5

The center is (3, -2)
The foci are at (3, -2±√29).