Question

Two cards are drawn from a standard deck of cards. Find each probability.
1. P(ace, then king) if replacement occurs
ace=4/52
king=4/52
(4/52)^2
2. P(heart, then club) if no replacement occurs
heart = 13/52
club=13/52
=(13/52)^2
?

Answer 1

If no replacement occurs for 2. then surely the p(club) will be 13/51 since there are now only 51 cards left in the pack?

Answer 2

2) I forgot if no replacement
heart = 13/52
club=13/52
(13/52)*(12/51) ?

Answer 3

1) m'I right?

Answer 4

No ... if no replacement then (13/52)*(13/51)

Answer 5

yes, that seems correct.

Answer 6

you still have 13 clubs but only 51 cards to choose from!

Answer 7

I'm confusing, which one?

Answer 8

p(heart then club) = (13/52)*(13/51) asuming no replacement

Answer 9

ok, than
P(ace, then king) ?

Answer 10

assuming replacement (4/52)*(4/52)

Answer 11

than
1) I'm correct
2) I just forgot reduce the denominator
?

Answer 12

yes :)

Answer 13

1. P(ace, then king) if replacement occurs

= 4/52 *4/52=1/169

1. P(ace, then king) if replacement occurs

4/52*4/51=4/663

Answer 14

raheen ... that is valid only if replacement does not occur on the (4/52)*(4/51)

Answer 15

ty,raheen is correct

Answer 16

if you take out an ace what is p(king)? 4/51

Answer 17

P(ace, then king) if replacement occurs
than deniminator keep the same

P(heart, then club) if no replacement occurs

than deniminator reduce to 51

Answer 18

yes

Answer 19

think about it in terms of ... if you do not replace the card, how many cards are left in the deck?

Answer 20

51

Answer 21

yes so if you want a king and they are all still in the deck then you have a 4/51 chance of picking a king