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Mathematics 21 Online
OpenStudy (anonymous):

A function is given by f(x) ln(e^x + e^-x +2) Find a) f ' (x) and b) f '' (x) Thank you ppl.

OpenStudy (lalaly):

d/dx ( lnf(x) ) = f'(x) /f(x)

OpenStudy (lalaly):

e^x -e^-x / e^x+e^-x +2

OpenStudy (anonymous):

lalaly, I have 8 options to choose from and that is not an option for f'(x)

OpenStudy (lalaly):

nw use the quotient rule for f''(x) (e^x -e^-x)(e^x+e^-x+2) -(e^x-e^-x)(e^x-e^-x) / (e^-x+e^x+2)^2

OpenStudy (lalaly):

wht are the options

OpenStudy (lalaly):

my answer can be simplifed to e^x - 1 / e^x +1

OpenStudy (anonymous):

lol both f'(x) and f''(x) should come from these: 1 / (e^x - e^-x) 2/e^x + e^-x + 2 e^x + e^x / e^x + e^-x + 2 e^ - e^-x / e^x + e^ -x + 2 2(e^2x + e^-2x) / (e^x + e^-x + 2)^2 2(e^x + e^-x)/(e^ + e^-x + 2)^2 - (e^x + e^-x) / (e^x - e^-x)^2 e^x - e^-x / e^2x + e^-2x

OpenStudy (anonymous):

what lalaly posted the first time is there, its the 4th one from the top.

OpenStudy (lalaly):

thanx joe :D ...

OpenStudy (anonymous):

Ooops sorry lalay, I missed it :( what about f ''(x) ?

OpenStudy (anonymous):

is that the fifth on on the list?

OpenStudy (lalaly):

wait i did not simplify it

OpenStudy (anonymous):

i think you get \[f'(x)=\frac{e^x-1}{e^x+1}\] is that an option?

OpenStudy (anonymous):

maybe easiest to use the quotient rule for f' in this form

OpenStudy (anonymous):

sorry satelite it's not ... lalaly has helped me with f ' (x) ... it's the fourth one on my list above.

OpenStudy (anonymous):

oh so i see. i should read more carefully. strange though...

OpenStudy (anonymous):

I still her solution for f '' (x) simplified though so i can see if that is the fifth or sixth on the list.

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