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\[(7+\sqrt{2})(8-3\sqrt{2})\]
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okay, so all we have to do is FOIL.
you should get: \[50-13\sqrt{2}\]
i did thank you
Rationalize the denominator of
\[(7)(8)+(7)(-3\sqrt{2})+(\sqrt{2})(8)+(\sqrt{2})(-3\sqrt{2})\] \[56-21\sqrt{2}+8\sqrt{2}-6\] \[50-13\sqrt{2}\]
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\[\sqrt{50}/\sqrt{5}\]
how do u rationalize the denominator
multiply to and bottom of that fraction by \[\sqrt{5}\]
i am sorry thats wrong
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i got \[\sqrt{10}\]
yeah, thats right
i was thinking about something else
or is it 5\[5\sqrt{5}/2\]
no, its is \[\sqrt{10}\]
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how about Rationalize the denominator of \[3/\sqrt{2}\]
When we multiply the top and bottom by \[\sqrt{2}\] we get : \[(3\sqrt{2})/(2)\]
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