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OpenStudy (anonymous):
Find the standard matrix for the orthogonal projection of R^3 onto the span{a_1,a_2} and confirm that the matrix is idempotent? a_1=(3, -4, 1) a_2=(2,0,3)
15 years ago
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OpenStudy (zarkon):
\[\left[\begin{matrix}\frac{113}{257}&\frac{-84}{257} &\frac{96}{257} \\ \frac{-84}{257} & \frac{208}{257} &\frac{56}{257} \\\frac{96}{257} & \frac{56}{257} &\frac{193}{257} \end{matrix}\right]\]
15 years ago
OpenStudy (anonymous):
Yeah that is the answer! how'd you get it though??
15 years ago
OpenStudy (zarkon):
I found an orthogonal basis for the span
then I found the projection matrix for each basis vector of my span
then I added the two matrices
15 years ago
OpenStudy (anonymous):
I can't get the answer for some reason.. did you use 1/a^t*a (a*a^T) for each vector?
15 years ago
OpenStudy (anonymous):
then add them together sorry I meant a^T
15 years ago
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OpenStudy (zarkon):
did you find an orthogonal basis first
15 years ago
OpenStudy (zarkon):
you should use \[\frac{v^Tv}{v\cdot v}\]
15 years ago
OpenStudy (anonymous):
Oh you used the gram schmidt process
15 years ago
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OpenStudy (anonymous):
okay thanks
15 years ago
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