Mathematics
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OpenStudy (anonymous):
how can i find Rank of matrix
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OpenStudy (anonymous):
m=1 3 1
4 2 0
6 0 2
OpenStudy (anonymous):
Find the row ehelon form and count the number of non-zero rows which is the rank
OpenStudy (anonymous):
echelon
OpenStudy (anonymous):
can please explain more please
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OpenStudy (anonymous):
1 x y
0 1 z
0 0 1
convert to this form by row and column operations and count the number of non-zero rows which in this case is 3 is the rank
OpenStudy (anonymous):
what about the column
OpenStudy (anonymous):
are u there?
OpenStudy (anonymous):
yes m here
OpenStudy (anonymous):
what ur question, not clear to me
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OpenStudy (anonymous):
in the of 4by 4 matrix how to determine the rank
OpenStudy (anonymous):
rank of this matrix is 3
OpenStudy (anonymous):
rank is found the same for any order square matrix
OpenStudy (anonymous):
but what about 3by 3 matrix
OpenStudy (anonymous):
u know row and column operations?
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OpenStudy (anonymous):
yes
what next
OpenStudy (anonymous):
change the matrix to the form
1 a b
0 1 c
0 0 1
and count how many non-zero rows are there that will be the rank
OpenStudy (anonymous):
u try ur and tell me
OpenStudy (anonymous):
3
OpenStudy (anonymous):
am i right
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OpenStudy (anonymous):
correct, same procedure for all other
OpenStudy (anonymous):
so the numbers of non-zero is know as ranks of matrix
OpenStudy (anonymous):
yes the numbers of non-zero rows in that form i told, it is called Echelon form
OpenStudy (anonymous):
now am geting u now
OpenStudy (anonymous):
what about the collum
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OpenStudy (anonymous):
are u there?
OpenStudy (anonymous):
i was a little far, now here, tell me
OpenStudy (anonymous):
i m not getting, what u say that "what about the column"
OpenStudy (anonymous):
I mean echelon form does it deal with colum
OpenStudy (anonymous):
if u do any thing with row and column the final matrix should be that i showed
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OpenStudy (anonymous):
did u get it now
OpenStudy (anonymous):
ok give example of 4by4 matrix
OpenStudy (anonymous):
1 0 2 3
2 3 1 6
1 2 6 2
1 3 0 4
change it to
1 x y z
0 1 t k
0 0 1 w
0 0 0 1
and tell me ur result
OpenStudy (anonymous):
4
OpenStudy (anonymous):
correct
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OpenStudy (anonymous):
example of 5by 5
OpenStudy (anonymous):
make randomly and solve it, try book examples and excercises that r always tricky
OpenStudy (anonymous):
am confuse but with ur explation an getting one or two fact
OpenStudy (anonymous):
the rank of matrix for 5by5 should 4 am right
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OpenStudy (anonymous):
@successboye O dear I went offline becoz of interuption in internet. B online when i m online and i will tell u all about it. Dont worry
OpenStudy (anonymous):
are u back
OpenStudy (anonymous):
m back where r u
OpenStudy (anonymous):
are u there
OpenStudy (anonymous):
Good day