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Mathematics 22 Online
OpenStudy (anonymous):

how can i find Rank of matrix

OpenStudy (anonymous):

m=1 3 1 4 2 0 6 0 2

OpenStudy (anonymous):

Here is a good link, don't feel like typing a long explanation http://stattrek.com/matrix-algebra/matrix-rank.aspx

OpenStudy (anonymous):

Find the row ehelon form and count the number of non-zero rows which is the rank

OpenStudy (anonymous):

echelon

OpenStudy (anonymous):

can please explain more please

OpenStudy (anonymous):

1 x y 0 1 z 0 0 1 convert to this form by row and column operations and count the number of non-zero rows which in this case is 3 is the rank

OpenStudy (anonymous):

what about the column

OpenStudy (anonymous):

are u there?

OpenStudy (anonymous):

yes m here

OpenStudy (anonymous):

what ur question, not clear to me

OpenStudy (anonymous):

in the of 4by 4 matrix how to determine the rank

OpenStudy (anonymous):

rank of this matrix is 3

OpenStudy (anonymous):

rank is found the same for any order square matrix

OpenStudy (anonymous):

but what about 3by 3 matrix

OpenStudy (anonymous):

u know row and column operations?

OpenStudy (anonymous):

yes what next

OpenStudy (anonymous):

change the matrix to the form 1 a b 0 1 c 0 0 1 and count how many non-zero rows are there that will be the rank

OpenStudy (anonymous):

u try ur and tell me

OpenStudy (anonymous):

3

OpenStudy (anonymous):

am i right

OpenStudy (anonymous):

correct, same procedure for all other

OpenStudy (anonymous):

so the numbers of non-zero is know as ranks of matrix

OpenStudy (anonymous):

yes the numbers of non-zero rows in that form i told, it is called Echelon form

OpenStudy (anonymous):

now am geting u now

OpenStudy (anonymous):

what about the collum

OpenStudy (anonymous):

are u there?

OpenStudy (anonymous):

i was a little far, now here, tell me

OpenStudy (anonymous):

i m not getting, what u say that "what about the column"

OpenStudy (anonymous):

I mean echelon form does it deal with colum

OpenStudy (anonymous):

if u do any thing with row and column the final matrix should be that i showed

OpenStudy (anonymous):

did u get it now

OpenStudy (anonymous):

ok give example of 4by4 matrix

OpenStudy (anonymous):

1 0 2 3 2 3 1 6 1 2 6 2 1 3 0 4 change it to 1 x y z 0 1 t k 0 0 1 w 0 0 0 1 and tell me ur result

OpenStudy (anonymous):

4

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

example of 5by 5

OpenStudy (anonymous):

make randomly and solve it, try book examples and excercises that r always tricky

OpenStudy (anonymous):

am confuse but with ur explation an getting one or two fact

OpenStudy (anonymous):

the rank of matrix for 5by5 should 4 am right

OpenStudy (anonymous):

http://en.wikipedia.org/wiki/Gaussian_elimination

OpenStudy (anonymous):

@successboye O dear I went offline becoz of interuption in internet. B online when i m online and i will tell u all about it. Dont worry

OpenStudy (anonymous):

are u back

OpenStudy (anonymous):

m back where r u

OpenStudy (anonymous):

are u there

OpenStudy (anonymous):

Good day

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