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Evaulate the integral by parts \[\int\limits_{0}^{1}y/e ^{2y} dy\]
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\[\int_0^1 \frac{y}{e^{2y} }dy\] ?
yah that
im not getting the correct answer
the answer is 1/4 - (3/4)(e^-2)
lets try this again \[\int ye^{-2y}dy\] \[\frac{y e^{-2y}}{-2} - \int\frac{e^{-2y}}{-2}\] \[ - \frac{ye^{-2y}}{2} - \frac{e^{-2y}}{4}\]
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so now when we put the limits
i did things wrong in my first attempt not this one atleast thats what i think lol \[-\frac{e^{-2}}{2} - \frac{e^{-2}}{4} + \frac{1}{4}\]
\[\frac{1}{4} - \frac{-3e^{-2}}{4}\]
ok i kinda get the steps now
good : )
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gotta change to e^-2y
yeah that makes it easy to think and perform in my first attempt i didn't do it and had trouble
yeah thats what i didnt do
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