Question

what is d/dx(1/sinx)

Answer 1

Gotta use the chain rule:
\[\frac{d}{dx}[\frac{1}{f(x)}] = -\frac{1}{(f(x))^2}\cdot \frac{d}{dx}[f(x)]\]
\[\implies \frac{d}{dx}[\frac{1}{sin(x)}] = -\frac{1}{sin^2(x)}\cdot cos(x) = -csc(x)cot(x)\]

Answer 2

i am confused

Answer 3

By?

Answer 4

ok,i hate calculas
i just hate it,but thanks polpak and hasir for helping me

Answer 5

Nothing to hate. Just have to practice and study.

Answer 6

my SAT,i need to cry

Answer 7

d/dx(1/sinx)

take this rule:
d/dx(a/u(x)) = -a.u'/u^2

Answer 8

instead of making things more comlicated in memorizing