Question

A flashlight battery has a lifetime of 5 hours and it is rated for 0.6 ampere-hours.

(a) What is the current that can be delivered by the battery?
(b) How much power can be delivered if the terminal voltage is 8 V?
(c) How much energy is stored in the battery?

Answer 1

a. If it has .6 ampere-hours means the battery can run a current of x amps for .6/x hours
From this we see that the current is .6/5hours = 0.12 amperes
b. Power= I*V= .12A*8V= 0.96 Watts
c. Power= energy/second
Energy= Power*#seconds= 0.96 Watts*5hours*(3600seconds/hour)=17280 joules
or E=17.28 kilojoules