Question

A spherical cloud of charge of radius R carries total charge Q. The charge is
distributed so that its density is spherically symmetric, i.e. it is a function of the
radial distance from the centre of the sphere.
Explain why the “charge cloud” is equivalent to a point charge of Q Coulombs
at the centre of the sphere.

Answer 1

please help me

Answer 2

use gauss' law.

Answer 3

explain please

Answer 4

xylem, this is your question? Whew, good luck buddy

Answer 5

that's is hard to me 2

Answer 6

lol its an annoying question i cant figure it out doing my head in

Answer 7

construct a gaussian surface surrounding the charge cloud.

Gauss's law demonstrates that the charge enclosed in any surface is equivalent to a point charge.

Answer 8

\begin{array}l\color{#FF0000}{\text{I}}\color{#FF7F00}{\text{ }}\color{#FF7F00}{\text{s}}\color{#FFFF00}{\text{h}}\color{#00FF00}{\text{o}}\color{#0000FF}{\text{u}}\color{#6600FF}{\text{l}}\color{#8B00FF}{\text{d}}\color{#FF0000}{\text{ }}\color{#FF0000}{\text{r}}\color{#FF7F00}{\text{e}}\color{#FFFF00}{\text{a}}\color{#00FF00}{\text{l}}\color{#0000FF}{\text{l}}\color{#6600FF}{\text{y}}\color{#8B00FF}{\text{ }}\color{#FF0000}{\text{r}}\color{#FF7F00}{\text{e}}\color{#FFFF00}{\text{v}}\color{#00FF00}{\text{i}}\color{#0000FF}{\text{s}}\color{#6600FF}{\text{e}}\color{#8B00FF}{\text{ }}\color{#FF0000}{\text{m}}\color{#FF7F00}{\text{y}}\color{#FFFF00}{\text{ }}\color{#FFFF00}{\text{P}}\color{#00FF00}{\text{h}}\color{#0000FF}{\text{y}}\color{#6600FF}{\text{s}}\color{#8B00FF}{\text{i}}\color{#FF0000}{\text{c}}\color{#FF7F00}{\text{s}}\color{#FFFF00}{\text{.}}\end{array}

Answer 9

gl search it yahoo answer .com maybe it's on there