PLEASE HELP ME ANSWER THESE 2 QUESTIONS TO THIS IMAGE.
-PICTURE IS UNDER THIS POST-

Question

anonymous · Answer

attachment

anonymous · Answer

$$7.\ \ 45\pi$$
You first get the area of the circle, which is 225pi.

Then, you multiply it by 72/360 to get 45 pi

anonymous · Answer

the next one is trickier to follow, but it's relatively straightforward.
You will need to use the answer you got in question 7.

anonymous · Answer

360/45?

anonymous · Answer

You need to bisect triangle DQE into 2 right triangles with height = $$cos(36)*15$$
and base = $$sin(36)*15$$ to help you find the area of the whole triangle.

The area of the entire triangle is then $$cos(36)*sin(36)*15*15$$

to approximate the area of the circle segment, you put this in the calculator: $$45\pi-(cos(36)*sin(36)*15*15)$$

to get $$8.\ \ a.\ 34.4$$

anonymous · Answer

I totally understand! thanx again!

anonymous · Answer

are you sure?