Question

factor completely:
4y²+20y+25 Please explain how you did it! Thank you!

Answer 1

you are supposed to recognize this as a "perfect square"
\[4y^2\] is the square of \[2y\],25 is the square of 5, and
\[20y=2\times 2y\times 5\]

Answer 2

so it factors as
\[(2y+5)^2\]
the explanation came first, then the answer

Answer 3

I think so

Answer 4

Yeah were supposed to make it a perfect square

Answer 5

But I don't know how to do a perfect square with three terms.

Answer 6

it looks like this:
\[a^2+2ab+b^2=(a+b)^2\]

Answer 7

in your case
\[a=2y, b=5, 2ab=20y\]

Answer 8

So 20y would stay the same?

Answer 9

so is this the answer: 2y+20y+5=(2y+5)²

Answer 10

no. you started with
\[4y^2+20y+25\] and that is equal to
\[(2y+5)^2\]

Answer 11

I'm really confused.