how to solve (x+2)^3/4=27

Question

anonymous · Answer

-(x+2)^-3/4=-1/27
 ......1
 - --------------= -1/27
 ..∜(x+2)^3
 
................1
 1/27 = -----------
 ..........∜(x+2)^3
 

(∜(x+2)^3)^4 = 27^4
 (x+2)^3 = 531,441
 x+2 = ∛(531,441)
 x= -2 +81
 x= 79 answer//

anonymous · Answer

$$\large{(x+2)}^{\frac{3}{4}}= 27$$
$$\large{(x+2)} = 27^{\frac{4}{3}}$$
$$x +2 = 3^4$$
$$x = 81-2$$
$$x = 79$$

anonymous · Answer

I thought it was$$\frac{(x+2)^3}{4} = 27$$

hero · Answer

I like Ishaan's solution better

anonymous · Answer

$$x+2=\pm27^{\frac{4}{3}}$$
$$x+2=\pm\sqrt[3]{27^4}$$
$$x+2=\pm3^4$$
$$x+2=81$$
$$x=79$$ or 
$$x+2=-81$$
$$x=-83$$

anonymous · Answer

i think in these cases you get two solutions

anonymous · Answer

but it is 1/3 power I don't think they have plus and minus like square root right ?
I am not sure

anonymous · Answer

on no i am wrong.  it is 
$$\sqrt[4]{(x+2)^3}$$ sorry

anonymous · Answer

can't take the fourth root of negative. ignore me.