I'm trying to find the field lines, x, of F(x,y,z)=(y-z,-x,x-y). Am I supposed to use the formula:\[\dot{\underline{x}}=\lambda(\underline{x})\underline{F}(\underline{x})\] for some scalarfield lambda? How does it work?
oh it's F(x,y,z)=(y-z,z-x,x-y)
\[\dot{\underline{x}}=\frac{d\underline{x}}{dt}\]by the way
Seems like some kind of method for graphing curl or divergence, something like that but I don't recognize the formula...
i think it needs more clarification ...
OK, see if he comes back....
looks like some sort of differential equation exercise perhaps ...
Field lines sounds like some sort of contour graph...
or force field jargon ... the closest thing I can come to online is: http://www.physicsforums.com/showthread.php?t=304499
Ok, that's a set of calculations, normally interpreting curl,div etc graphically is something of a pain, I would be quite interested if there was some better way of doing that....
Of course I should have checked Wiki, doesn't explain the formula though... This article is about the modern use of "field lines" as a way to depict electromagnetic and other vector fields. "Modern" , that's why I don't know it, lol.
\[\dot{\underline{r}}(t)=(\frac{dx(t)}{dt},\frac{dy(t)}{dt},\frac{dz(t)}{dt})\] So you get a system of linear equations. lambda(x) doesn't have an effect on the direction so you can choose anything you want for that I believe. The answer to this question is supposedly \[x^{2}+y^{2}+z^{2}=c_{1} \]\[x+y+z=c_{2}\] so you get circles.
The line underneath letters means that they're vectors.
Yes, I got that, I will have another look at this a bit later on...
Did I say linear equations, I meant differential equations.
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