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Mathematics 50 Online
OpenStudy (anonymous):

Given the following sets, select the statement below that is true. A = {b, l, a, z, e, r}, B = {b, a, l, e}, C = {a, b, l, e}, D = {l, a, b}, E = {l, D ⊆ E and C ⊂ A B ⊆ C and B ⊆ E E ⊆ B and B ⊆ C B ⊂ E and D ⊆ A D ⊆ E and E ⊂ A

OpenStudy (anonymous):

Do you know what those symbols mean?

OpenStudy (anonymous):

kinda

OpenStudy (anonymous):

C with underline is improper subset. C means proper

OpenStudy (anonymous):

what does it mean to be improper subset?

OpenStudy (anonymous):

or proper for that matter.

OpenStudy (anonymous):

i dont know that.. does say in the ebook:(

OpenStudy (anonymous):

Ok. A subset (improper) is just a set that has some OR all of the same elements as the original. That means that if \(Q \subseteq R\) Then every element in Q is also in R.

OpenStudy (anonymous):

If instead we have \(P \subset R\) That means that every element in P is also in R BUT not every element in R is in P.

OpenStudy (anonymous):

So P doesn't equal R. Q could equal R though.

OpenStudy (anonymous):

So now that we know that. Lets look at your problem.

OpenStudy (anonymous):

Oh.. Your E set got cut off.

OpenStudy (anonymous):

Can you type it out for me?

OpenStudy (anonymous):

A = {b, l, a, z, e, r}, B = {b, a, l, e}, C = {a, b, l, e}, D = {l, a, b}, E = {l, a}

OpenStudy (anonymous):

D ⊆ E and C ⊂ A B ⊆ C and B ⊆ E E ⊆ B and B ⊆ C B ⊂ E and D ⊆ A D ⊆ E and E ⊂ A

OpenStudy (anonymous):

so D and E have l,a the same

OpenStudy (anonymous):

Ok. So the first choice:\[D\subseteq E \text{ and } C \subset A\] Is each element of D also in E? Is each element in C also in A?

OpenStudy (anonymous):

not all of them for D and E and yes all the same for C and A

OpenStudy (anonymous):

Ok, so you have \(\text{ False and True } \implies False\) Therefore it is not the first option.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

B and C and B and E

OpenStudy (anonymous):

So the second option:\[B \subseteq C \text{ and } B \subseteq E\] Is each element in B also in C? And is each element in B also in E?

OpenStudy (anonymous):

b and C have all the same elements

OpenStudy (anonymous):

but b and E are same but different

OpenStudy (anonymous):

so that would be True and False=False

OpenStudy (anonymous):

Right.

OpenStudy (anonymous):

Option 3?

OpenStudy (anonymous):

E and B and B and C

OpenStudy (anonymous):

Is E a subset of B?

OpenStudy (anonymous):

no its not... same but differnent

OpenStudy (anonymous):

Hold up

OpenStudy (anonymous):

so it would be False and True =False

OpenStudy (anonymous):

We don't care if they are the same.

OpenStudy (anonymous):

That would be B = E

OpenStudy (anonymous):

We want to know. Is every element in the subset also in the original set.

OpenStudy (anonymous):

So in this case, Is E a subset of B. Is every element in E also in B?

OpenStudy (anonymous):

even if B has other elements that arent the same?

OpenStudy (anonymous):

Yes!

OpenStudy (anonymous):

yes E is a subset of B

OpenStudy (anonymous):

Right!

OpenStudy (anonymous):

B is NOT a subset of E. But E IS a subset of B

OpenStudy (anonymous):

and B and C have the same elements

OpenStudy (anonymous):

Because l and a are both in B. And since B and C are the same, B is an improper subset of C also.

OpenStudy (anonymous):

ok if it was switched around it would be false. cuz B dont have same elements as E

OpenStudy (anonymous):

Right!

OpenStudy (anonymous):

so my answer would be E and B and B and C

OpenStudy (anonymous):

E subset B and B subset C yes.

OpenStudy (anonymous):

ok now i starting to understand this a little bit more.

OpenStudy (anonymous):

That's awesome. Keep practicing ;)

OpenStudy (anonymous):

ty :)

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