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Mathematics 20 Online
OpenStudy (anonymous):

. Given the following set, select the statement below that is true. A = {q, r, s, t, u} p ∈ A 5 ∈ A r ∉ A s ∈ A A ⊆ Ø

OpenStudy (aroub):

s ∈ A

OpenStudy (anonymous):

s belongs A

OpenStudy (anonymous):

can u explain to me how to do this problem and figure it out? please

OpenStudy (anonymous):

just dont tell me the answer please

OpenStudy (anonymous):

\(\in\) means 'in' or that \(a \in B\) means that there is an 'a' in the set B.

OpenStudy (anonymous):

If there is a line through it like \(\notin\) that means that the item is NOT in the set.

OpenStudy (aroub):

as u can see u have in set A {q, r, s, t, u} the letter s , so belongs to the set a

OpenStudy (aroub):

so S belongs to set A ****

OpenStudy (anonymous):

So looking at the first option \(p \in A\) we check the set A. There is no p in it. Therefore this option is false.

OpenStudy (anonymous):

There is also no 5 in A. Therefore option 2 is false.

OpenStudy (anonymous):

The third option says r is NOT in A. We look at A. r is in there. Therefore this option is false.

OpenStudy (anonymous):

Next option says \(s \in A\). There is an s in A. Therefore this is true.

OpenStudy (anonymous):

so it would be the last one? cuz there is no 0 in A?

OpenStudy (anonymous):

im confused!

OpenStudy (anonymous):

No. It would be the 4th one. \(s \in A\) is TRUE. s is an element of A.

OpenStudy (anonymous):

The last one is false because it's saying that A is a subset of an empty set. Which would only be true if A were empty and it's not.

OpenStudy (anonymous):

there is 5 elements in A thats how thats the answer

OpenStudy (anonymous):

What?

OpenStudy (anonymous):

it says 5 ∈ A there is NO 5 in A

OpenStudy (anonymous):

That is option 2.

OpenStudy (anonymous):

there is 5 elements in A

OpenStudy (anonymous):

And you are right. It is false.

OpenStudy (anonymous):

That means the cardinality of A is 5, but there is no 5 in A. So it cannot be 5 ∈ A

OpenStudy (anonymous):

ok so s in A its true

OpenStudy (anonymous):

yes.

OpenStudy (anonymous):

so that would be the answer.. :)

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ty :)

OpenStudy (anonymous):

if i post a Venn diagram will u help me out? its asking for subset of P using set notations

OpenStudy (anonymous):

OpenStudy (anonymous):

I'm not sure why you need Q there.

OpenStudy (anonymous):

the set notation i have written down would be P={u,l,c,k}

OpenStudy (anonymous):

That's P yes

OpenStudy (anonymous):

P is a subset of P. So that will be your first one.

OpenStudy (anonymous):

Thats part of the question... thats what they are asking for is all of subsets of P

OpenStudy (anonymous):

Now list all the subsets of P that have cardinality of 3

OpenStudy (anonymous):

it would be the P={u,l,c,k}

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

Huh? That is P. That is one of the subsets of P. That is not all of the subsets.

OpenStudy (anonymous):

the other one is Q and its not part of P

OpenStudy (anonymous):

I don't understand what that has to do with listing the subsets of P.

OpenStudy (anonymous):

yea me either..this is the problem the professor game me

OpenStudy (anonymous):

The subsets of P depend only on the elements in P.

OpenStudy (anonymous):

am i missing subsets of P? wouldnt it be just the ones that are in P only?

OpenStudy (anonymous):

These are the subsets of P: {u,l,c,k} {u,l,c} {u,l,k} {u,c,k} {l,c,k} {u,l} {u,c} {u,k} {l,c} {l,k} {c,k} {u} {l} {c} {k} {}

OpenStudy (anonymous):

oh ok.. so i have to write it all out ... gottcha

OpenStudy (anonymous):

all the way down to {}

OpenStudy (anonymous):

when it asks for subsets u have to write them ALL out..

OpenStudy (anonymous):

If it asks for all subsets. I would write them all.

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