Question

Trying to simplify: (Square root x-2) + 5 divided by (square root x-2) all over x-2. Can anyone help? Thanks!

Answer 1

I hate these.

Answer 2

sqrt(x-2)+5 / sqrt(x-2)(x-2)....yes?

Answer 3

Multiplying top and bottom by sqrt(x-2) looks like a good bet...

Answer 4

No, ((\sqrt{x-2})+ 5/\sqrt{x-2}) / x-2\]

Answer 5

That's the same...

Answer 6

1/2 divided by 2 is 1/4...

Answer 7

\[\sqrt{x-2}+5 \over \sqrt{x-2}(x-2)\]

Answer 8

sorry its backwards but thats what im trying to solve

Answer 9

Are they all 2's in the picture?

Answer 10

except for the 5 on the very top

Answer 11

Well, that's straightforward, just add 'em

6 sqrt(x-2) /5(x-2)

Answer 12

U see?

Answer 13

maybe? - working on where you got the 6

Answer 14

Just add at the top, LCD is 5 so u have 5 +1 sqrt(x-2)'s

Answer 15

and the 5 goes to the bottom along with (x-29

Answer 16

I see. Thanks.

Answer 17

x-2, sorry

Answer 18

Wait a minute I am reading it upside down....

Answer 19

It actually says sqrt(x-2) + 5/sqrt(x-2) is that right?

Answer 20

yes

Answer 21

Ah Ok, moment..

Answer 22

OK; LCD is sqrt(x-2) so adding


(x+3) / (x-2) sqrt(x-2) is what u want to simplify....

Answer 23

So multiply top and bottom by sqrt(x-2) to get

sqrt(x-2) (x+3) / (x-2)^2 is your answer.

Answer 24

Where does the (x+3) come from?

Answer 25

Your LCD is sqrt(x-2) so when you add you get

sqrt(x-2)sqrt(x-2) +5 = x-2 +5 = x+3

Answer 26

i finally see

Answer 27

:-) Got there in the end (try to use the equation editor, makes life easier with the odd ones).

Answer 28

ok thanks

Answer 29

estudier's solution boils down to\[\frac{x+3}{(x-2)^{3/2}} \]if the numerator and the denominator are divided by\[\sqrt{(x-2) } \]