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Mathematics 18 Online
OpenStudy (anonymous):

Multiply. Express product in lowest terms: y^2+2y-63 / y^2+3y -70 * y^2-2y-80/y^2+17y+72

OpenStudy (bme89):

First you have to factor all of the terms. Then you can simplify it down

OpenStudy (bme89):

It is factored to the following fraction: The numerator: (y+9)(y-7)(y-10(y+8) The denominator: (y-10)(y+7)(y+9)(y+8)

OpenStudy (bme89):

Then cancel the terms to leave (y-7)/(y+7)

OpenStudy (bme89):

But remember to include that in the simplified expression, y cannot equal 10, -9, or -8. This is because the original expression will give 0/0 while the simplified expression will not give 0/0.

OpenStudy (anonymous):

If the intended problem expression is ( (y^2 + 2 y - 63)/(y^2 + 3 y - 70) ) * ( (y^2 - 2 y - 80)/(y^2 + 17 y + 72) ) then\[\frac{y-10}{y+10} \]is the answer.

OpenStudy (anonymous):

y-7 / y+7 was a wrong answer?

OpenStudy (anonymous):

@ SeattleSunGirl Is the form of your problem expression (a+b)/(c+d) or something else? My solution assumed (a+b)/(c+d) where a, b, c and d are your quadratic expressions.

OpenStudy (anonymous):

Sorry. I made a mistake. I assumed a form of (a/b)*(c/d) , not (a+b)/(c+d) as stated above.

OpenStudy (anonymous):

No no, your answer was right :)

OpenStudy (anonymous):

Thank you. In the future you might insert parenthesis to eliminate any chance that the problem form will be being questioned.

OpenStudy (bme89):

oh sorry, yeah, robtobey is right. My mistake was on the denominator, (y+10)(y-7). which leaves (y-10)/(y+10)

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