Expand (x+y)^3?
x^3+3a^2b+3ab^2+b^3
Urge to delete rising..
To expand you basically do a lot of distribution
1 1 2 1 1 3 3 1 1 4 6 4 1 1 5 10 10 5 1 this some of the levels of the pascal triangle this an easy way to memorize coefficients of (x+y)^n
Memorize schemorize.. Nobody wants to keep this in their brain
Ha no I don't do well with memorization
You don't need to memorize pascal, just add two term from above
\[(x+y)^n=x^n++x^{n-1}y+x^{n-2}y^2+ \cdot \cdot \cdot +x^2y^{n-2}+xy^{n-1}+y^n\]
no seriously it is the most easy thing to memorize
do you not see an easy pattern all you are doing is adding the two number above to find the one below
\[(x+y)^3\]\[=(x+y)(x+y)(x+y)\]\[=(x^2 + 2xy + y^2)(x+y)\]\[=x^2(x+y) + 2xy(x+y) + y^2(x+y)\]\[=x^3 + x^2y + 2x^2y + 2xy^2 + xy^2 + y^3\]\[=x^3+ 3x^2y + 3xy^2 + y^3\]
You already know from your last problem how to do the first two factors (x+y)(x+y)
Then you take that result and distribute the last factor (x+y) to each term in that result
1 1 2 1 1 (1+2) (2+1) 1 1 1+(1+2) (2+1+1+2) 1+(2+1 1 so on.....................
Then you distribute and combine like terms
Okay I think I get it
Make sure, or figure out what you're shaky on
I worked through it by myself and I understand it for sure. Thanks!
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