Mathematics
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OpenStudy (anonymous):
Simplify: squareroot of (x) / (x) ?
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OpenStudy (anonymous):
?
OpenStudy (anonymous):
\[\frac{\sqrt{x}}{x}\]?
OpenStudy (anonymous):
\[\sqrt{x/x}=1\]
jimthompson5910 (jim_thompson5910):
If it's \[\frac{\sqrt{x}}{x}\], then you can't simplify
If it's \[\sqrt{\frac{x}{x}}\], then the answer is 1.
OpenStudy (anonymous):
or
\[\sqrt{\frac{x}{x}}\]
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OpenStudy (anonymous):
Ignore the questionmark
OpenStudy (anonymous):
Please clarify the question.. Is it:
1) \(\huge\frac{\sqrt{x}}{x}\)
2)\(\huge \sqrt{\frac{x}{x}}\)
OpenStudy (anonymous):
the first one
OpenStudy (anonymous):
@polpak why are yours big?
OpenStudy (anonymous):
then the answer is 1/sqrtx
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OpenStudy (anonymous):
So they are readable.
OpenStudy (anonymous):
\[\frac{\sqrt{x}}{x}=\frac{1}{\sqrt{x}}\]
OpenStudy (anonymous):
\[1/\sqrt{x}\]
is the answer
OpenStudy (anonymous):
no i mean how did you do it?
OpenStudy (anonymous):
Right click it. Select view source
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OpenStudy (anonymous):
\[\sqrt{x}/\sqrt{x}*\sqrt{x}=1/\sqrt{x}\]
OpenStudy (anonymous):
\[\large \frac{\sqrt{x}}{x} = \frac{x^{\frac{1}{2}}}{x^1} = x^{\frac{1}{2} - 1} = x^{-\frac{1}{2}} = \frac{1}{\sqrt{x}}\]
OpenStudy (anonymous):
This is assuming you recall how to convert radicals into fractional exponents.
OpenStudy (anonymous):
Vaguely