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Mathematics 20 Online
OpenStudy (anonymous):

Simplify: squareroot of (x) / (x) ?

OpenStudy (anonymous):

?

OpenStudy (anonymous):

\[\frac{\sqrt{x}}{x}\]?

OpenStudy (anonymous):

\[\sqrt{x/x}=1\]

jimthompson5910 (jim_thompson5910):

If it's \[\frac{\sqrt{x}}{x}\], then you can't simplify If it's \[\sqrt{\frac{x}{x}}\], then the answer is 1.

OpenStudy (anonymous):

or \[\sqrt{\frac{x}{x}}\]

OpenStudy (anonymous):

Ignore the questionmark

OpenStudy (anonymous):

Please clarify the question.. Is it: 1) \(\huge\frac{\sqrt{x}}{x}\) 2)\(\huge \sqrt{\frac{x}{x}}\)

OpenStudy (anonymous):

the first one

OpenStudy (anonymous):

@polpak why are yours big?

OpenStudy (anonymous):

then the answer is 1/sqrtx

OpenStudy (anonymous):

So they are readable.

OpenStudy (anonymous):

\[\frac{\sqrt{x}}{x}=\frac{1}{\sqrt{x}}\]

OpenStudy (anonymous):

\[1/\sqrt{x}\] is the answer

OpenStudy (anonymous):

no i mean how did you do it?

OpenStudy (anonymous):

Right click it. Select view source

OpenStudy (anonymous):

\[\sqrt{x}/\sqrt{x}*\sqrt{x}=1/\sqrt{x}\]

OpenStudy (anonymous):

\[\large \frac{\sqrt{x}}{x} = \frac{x^{\frac{1}{2}}}{x^1} = x^{\frac{1}{2} - 1} = x^{-\frac{1}{2}} = \frac{1}{\sqrt{x}}\]

OpenStudy (anonymous):

This is assuming you recall how to convert radicals into fractional exponents.

OpenStudy (anonymous):

Vaguely

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